0=-0.19x^2+8

Solution for 0=-0.19x^2+8 equation:

0=-0.19x^2+8

We move all terms to the left:

0-(-0.19x^2+8)=0

We add all the numbers together, and all the variables

-(-0.19x^2+8)=0

We get rid of parentheses

0.19x^2-8=0

a = 0.19; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·0.19·(-8)
Δ = 6.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.08}}{2*0.19}=\frac{0-\sqrt{6.08}}{0.38}
=-\frac{\sqrt{}}{0.38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.08}}{2*0.19}=\frac{0+\sqrt{6.08}}{0.38}
=\frac{\sqrt{}}{0.38}
$